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Home Q & A Board Science-Related Homework Help High School Level Science
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o2blea o2blea
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11 years ago
I need to identify what theparents of fruit flies were (heterozygous, homozygous) and what the genes are (x-linked, autosomal, etc).
      All I know is that they produced 600 flies: 341 completely normal, 125 normal wings and eyeless, 108 dumpy wings with eyes, and 26 dumpy wings and eyeless. I don't know how to do this with multiple genes..
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wrote...
#1
11 years ago
This is a dihybrid cross.
Let the gene for normal wings be- 'N' and for dumpy wings be 'n'
Let the gene for eyes be 'E' and for eyeless be 'e'.
Then the parents are-
NnEe  X  NnEe

Gametes- NE, Ne, nE, ne (for both parents)

When u'll draw a punnet square with the above gametes, you'll get a phenotypic ratio 9:3:3:1

You can note that 341 fruit flies in your case are appox (9/16)th of 600.
Thus, it is a dihybrid cross with general phenotypic ratio 9:3:3:1 or 341:125:108:26
THUS THE PARENTS WERE HETEROZYGOUS.
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