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rivera5454 rivera5454
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12 years ago
If the average molecular weight of a deoxynucleotide monophosphate (dNMP) or base is 330, hence base pair is 660, how much genomic DNA would a worm (C elegans) cell contain? The haploid C. elegans genome containing 8.0*10^7 base pairs, although the cell is diploid. If each hermaphrodite worm always contains 959 cells how much DNA would 1 worm contain?

I don't know how to do it Frowning Face so please include all steps.
THANK YOU VERY MUCH!!!!
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wrote...
12 years ago
"The haploid C. elegans genome containing 8.0*10^7 base pairs, although the cell is diploid." so you have  

8.0*10^7*2 base pairs per cell x 959 cells/worm x 660 amu/base pair

That giv es you an answer in amu. If you want g, divide by Avogadro's number.

that's all!
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