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tom tom
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11 years ago
Suppose that a rock contains 0.539 mg of 206Pb. If the current rock specimen contains 2.035 mg of 238U, how many mg of 238U were in the original rock specimen?
a. 0.539 mg
b. 0.623 mg
c. 2.658 mg
d. 2.035 mg

i understand that nuclear chemistry is probably at work, and that there is probably a formula to solve this problem, but i just do not know it
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Replies
wrote...
11 years ago
It must be c, because the answer must have a value greater than the mass of lead + the mass of uranium. (fission decay)

The other answers are not possible.
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