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ryobu ryobu
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8 years ago
 Consider the following formulas: nPr = (n!/(n-r)!) and nCr = (n!/(n-r)!r!).
Given the same values for n and r in each formula, which is the smaller value, P or C? How does this relate to the concept of counting the number of outcomes based on whether or not order is a criterion?
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Government in America: People, Politics, and Policy

Government in America: People, Politics, and Policy


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Staff Member
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8 years ago
 The combination value will be smaller, since order is not important. For example, ABC is equivalent to ACB and would not be counted twice.  If, however, r is 0 or 1 then nPr = nCr.
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ryobu Author
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8 years ago
If only I had more time to submit my work, I would have gotten it right Undecided Your answer was right.
- Enrolled in an AP law course
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