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ohHminus ohHminus
wrote...
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8 years ago
What concentration of NH4NO3 is required to make [OH–] = 1.0   10–5 in a 0.200-M solution of NH3?

In my professors explainations, they do an ICE table and she automatically made NH4 initially equal to 0.78 M. Can you explain how she got this number?
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wrote...
Valued Member
Educator
8 years ago
Hello there,

There is a very similar question found in the attachment below. See if it helps, and if it doesn't, give me another shout!
 Attached file 
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ohHminus Author
wrote...
8 years ago
Hello there,

There is a very similar question found in the attachment below. See if it helps, and if it doesn't, give me another shout!

So I worked the problem and solved for NH4 getting 0.36 M for the final concentration, but for some reason its still not clicking as to where to get the .78. To solve for NH4 I just ignored that bit, skipped the ice table and solved by using "small x-approximation" as my professor calls it.
wrote...
Valued Member
Educator
8 years ago
Did the document I uploaded provide any insight?
wrote...
5 years ago
thank you!
wrote...
5 years ago
Thank You
wrote...
4 years ago
Thank you
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