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New Topic  
thesurgeon thesurgeon
wrote...
Posts: 5
Rep: 0 0
8 years ago
Consider the genetic map below of loci a-g, where the distance between loci are indicated in map units.
a-5-b-20-c-10-d-2-e-25-f-1-g
a) Calculate the frequency of ac gametes from an Ac/aC genotype.
b) BcE from bce/BCE
c) bFG from bfg/BFG
d) the frequency of BCD/Bcd from bCd/BcD x BCd/BcD
e) the frequency of aBcDeFg/aBcDeFg progeny from a mating of ABcDefg/abCdEFG x AbCDeFg/aBcDEfG
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What I tried to do:
a) recombination must happen between A and c in order to get the phenotype AC/ac , therefore the frequency is the distance between a and c which is 25u , so the frequency of the gamete is 25% (or should it be 25% * 50% because we multiply by the chance of getting the ac gamete?)

b)2 recombinations must happen between b and c & c and e , therefore the frequency is 20%*(10+2)% = 2.4% (or should it be 2.4% * 50% for the same reason as part a ?)

c) one recombination between b and f -> 20+10+2+25= 57% (or 57% * 50% ? )

d) and e) How is it possible to have recombinations in  both parents? I don't see any way to solve it without having recombinations in both parents...
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