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juliejusu juliejusu
wrote...
Posts: 53
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11 years ago

isn't the equation V = IR ?
(V- voltage, I- current, R- resistance)
Right now I have one series circuit with a voltage of 6V, a current of 3A, and two resistors each with 1?.
How do I calculate the voltage drop of this circuit?
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wrote...
11 years ago
Another simple Ohms Law problem - I love 'em!
Series circuit, add the resistances. Rt = 2 Ohms. E (or V) = 6, I = 3.

Let's simplify Ohms law thus:
P = Power in Watts
E = EMF (Electro Motive Force) in Volts
I = Current in Amperes
R = Resistance in Ohms

Total:
P = 18 Watts
E = 6 (X 3 = Power)
I = 3 (X 2 = Volts)
R = 2

Drop across one resistor & power:
P = 9
E = 3
I = 3
R = 1

Did I make that clear?
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