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irina irina
wrote...
Posts: 919
11 years ago
For example, how would I solve an equation that looks like "(a^2)^0"?
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wrote...
11 years ago
Anything raised to power 0 is equal to 1, therefore

(a^2)^0 = 1
wrote...
11 years ago
i am not sure.. only in algebra 1.. is it 1? cuz isnt anything to the 0 power 1 ?? not sure.. sorry if wrong.. trying to help..
wrote...
11 years ago
If I remember correctly from Math II last term, anything with 0 as an exponent is 1.
wrote...
11 years ago
anything raised to the power of 0 is equal to 1

so

(a^2)^0 = 1

why?
because (x^m)/(x^n) = x^m-n. anything divided by itself is 1.

so x^3/x^3 = x^3-3 or x^0 = 1
if x = 3 then
27/27 = 1
if x = 2 then
8/8 = 1
wrote...
11 years ago
We have ( a^2)^0 = 1 => a^2 =1 =>a = 1 .
wrote...
11 years ago
That's not true: 0^0 is an indeterminate form which can be made to be "any value" by taking different limits which evaluate to 0^0. Usually, 0^0 is taken to be 1 because many formulas fail if it is anything else; it is little more than a convenience.
wrote...
11 years ago
Anything raised to the power of 0 is equal to 1!
wrote...
11 years ago
anything to the power of 0 is 1. so (x)^0 always = 1, even if its 0^0
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