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asaf asaf
wrote...
Posts: 32
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12 years ago

Under the conditions of:
400 celsius degrees, 350 barr
We mix Nitrogen and Hidrogen at a rate of 3:1 (correspondly)
In equilibrium we get that 50% of the product is Amonia

N2 (g) + 3H2 (g) -> 2NH3 (g)

A) Calculate the equilibtium constant of pressure: Kp ?
B) Calculate the free Gibbs energy under that conditions? [Kj/mol]
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Replies
wrote...
#1
12 years ago
Your expression is as follows: Kp= [NH3]2/[N2][H2]3

Gibbs Free Energy: \({\Delta}\)G  =  \({\Delta}\)H  -  T\({\Delta}\)S
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