× Didn't find what you were looking for? Ask a question
Top Posters
Since Sunday
a
5
k
5
c
5
B
5
l
5
C
4
s
4
a
4
t
4
i
4
r
4
r
4
Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
New Topic  
EA EA
wrote...
Posts: 223
Rep: 7 0
8 years ago
you have 25 mL of 8% NaOH (w/v). What is the minimum volume of 12% HCl (w/v) required to neutralize the acid?
Read 319 times
1 Reply

Related Topics

Replies
wrote...
#1
8 years ago
8%NaOH means 8g in 100 mL
Let us set up the ratio
x/25= 8/100
x= 2g
hence moles of NaOH in 2g = mass/molar mass= 2/40=0.05 moles
NaOH+ HCl ---> NaCl    +  H2O
hence moles of HCl required = 0.05 moles
mass of HCl = 0.05 *36.5 =1.825g
now volume required
1.825g/vol = 12g /100 ml
vol = 1.825*100/12 mL
solve it
Online Chemistry Tutor, AP Chemistry Tutor,
Organic Chemistry Tutor
IB Chemistry Tutor
New Topic      
Quick Reply
Explore
Post your homework questions and get free online help from our incredible volunteers
  868 People Browsing
Start New Topic Take the Tour CoursesNew Study Tools Topics Trending Browse by Textbook
Live Chat
Related Images
  
 14847
  
 92
  
 148
Your Opinion
Do you believe in global warming?
Votes: 370
Previous poll results: Which 'study break' activity do you find most distracting?