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Home Q & A Board Science-Related Homework Help Physics
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soccerguy787 soccerguy787
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11 years ago
There are three 160 watts light bulbs and a radio with an internal resistance of 43.0 ohms plugged into the living room electrical outlets. You decide to have a break and have a snack, turning on the pop-corn machine that draws 9.00 A. How much electrical power are you using? Data: Assume the electric company provide you with 110 V potential difference.
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wrote...
#1
11 years ago
So you need the Total Power.

P(total) = (160*3) + P(radio) + P(pop-corn machine)

P(radio) = V^2/r
            = (110^2)/43
            = 281.3954

P(popcorn machine) = V*I
                              = 110*9
                              = 990

P(total) = 480 + 281.3954 + 990
            = 1751.3954 W
wrote...
#2
11 years ago
iamSvper is correct. But I have not heard of a radio that draws this amount of huge power. Is it 430 ohms or 43 ohms??
wrote...
#3
11 years ago
1751.39 watts or about 1.75 killowatts
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