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RADIOhead RADIOhead
wrote...
Posts: 46
Rep: 1 0
12 years ago
i believe it C. correct me if i'm wrong

Sex determination in humans is a chance event. a family consisted of nine boys, including 2 sets of twin boys. each pair of twins made a pitcher-catcher combination on a baseball team. the family would like to have a daughter. what is the chance that their tenth child will be a girl?
a. 25%
b. 50%
c. 10%
d. (1/2)^10
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9 Replies

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wrote...
Staff Member
12 years ago
Isn't it always a 50% chance lol Neutral Face
Shomakasin
- Master of Science in Biology
- Bachelor of Science
wrote...
On Hiatus
12 years ago Edited: 12 years ago, Bio_World100
I believe you have to use the BINOMIAL THEOREM for this question.  

I am not sure if you've learned the binomial theorem before, but here's the general rule:

(a + b)^n = a^n + a^n-1(b) + a^n-2(b^2) + a^n-3(b^3) + ... b^n

Note: In each of these terms, there is usually a coefficient in front, except for the first and last terms (a^n and b^n).  You can find the coefficient of each term from Pascal's Triangle.

n = the size of the sample.  

There are one of two possible outcomes:

a = probability of being a boy
b = probability of being a girl  

The value of n is = 10 since there will be 9 boys and 1 girl.  

So, your binomial theorem for n = 10 would be:

(a + b)^10 = I am not going to expand the whole thing, but the term you would have to look for is 10(a^9)(b^1).  This is because there would be 10 children in total of which there will be 9 boys and 1 girl.  So, if you look at Pascal's Triangle, find the row with n = 10 and once you find that, you should be able to locate the term 10(a^9)(b^1).

So, for each child, the probability of being a girl is 0.5 and the probability of being a boy is 0.5: 0.5 + 0.5 = 1

So P(boy) = 0.5 & P(girl) = 0.5...So, a & b are = 0.5

So, your answer would then be 10(0.5)^9(0.5)^1.  The answer comes out to 0.009765625.  One of the choices given in your question is (1/2)^10 = 0.000976562.  There is an extra "0" in your choice.

So, I think the answer is D.

Hope that helps.   Slight Smile
padre,  bio_man,  Shomakasin
wrote...
12 years ago
Since they have already had 9 kids, no matter what sex the kids are, the 10th kid is 50% likely to be a girl and anotehr 50% to be a boy.
The "advanced" solution posted above is wrong.  If the question is:
A couple plans to have 10 kids.  What is the probability that all of them are boys?
Then Bio_World100's answer is correct...
But it's not.

(Use common sense here.  The past kids' genre doesn't affect the next one.)
wrote...
On Hiatus
12 years ago
Since they have already had 9 kids, no matter what sex the kids are, the 10th kid is 50% likely to be a girl and anotehr 50% to be a boy.
The "advanced" solution posted above is wrong.  If the question is:
A couple plans to have 10 kids.  What is the probability that all of them are boys?
Then Bio_World100's answer is correct...
But it's not.

(Use common sense here.  The past kids' genre doesn't affect the next one.)

Thanks for correcting me Thanos. 

To RADIOhead:

BTW, what is the correct answer to this question?  Just curious!  Smiling Face with Open Mouth

Shomakasin
wrote...
Staff Member
12 years ago
So who, ultimately, is right? Thinking Face
- Master of Science in Biology
- Bachelor of Science
wrote...
On Hiatus
12 years ago
So who, ultimately, is right? Thinking Face

We'll have to wait and find out!  Face with Rolling Eyes
RADIOhead Author
wrote...
12 years ago
Sorry guys. I was never told the correct answer  Frowning Face
wrote...
Staff Member
12 years ago
Sorry guys. I was never told the correct answer  Frowning Face

Thanks anyways
NicholasCatrow
- Master of Science in Biology
- Bachelor of Science
wrote...
Staff Member
7 years ago
The answer has been verified as B - 50%.
- Master of Science in Biology
- Bachelor of Science
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