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 2. An auto accelerates forward from 7.0 m/s at a uniform 0.71 m/s2. It travels a distance of 1.033 km while accelerating. (a) How fast is the auto moving just as it is traveled the 1.033 km? Explain (b) How many seconds did it take to travel the 1.033 km?a. from v^2 – u^2 = 2aSu = 7 m/sa= o.71 m/s^2S = 1.033km – 1033mV^2 - 7^2+2x0.7x1033V = sqrt(7^2+2x0.7x1033)V = 38.9340468 m/s or 39 m/sb.Now from t = 38.9340468 -7/0.71t = 44.9775307 s or 45 s
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