Top Posters
Since Sunday
p
6
I
6
h
5
k
5
a
5
J
5
k
5
r
5
O
5
x
5
d
4
s
4
New Topic  
Chery Chery
wrote...
Posts: 3587
7 years ago
A guitar-like stringed instrument has a string that is 16 cm long.  It sounds the musical note A (440 Hz) when played without fingering. By what distance should you shorten it to play the note C (523 Hz)?
A) 2.5 cm
B) 1.7 cm
C) 3.4 cm
D) 4.2 cm
Textbook 
College Physics

College Physics


Edition: 1st
Authors:
Read 843 times
5 Replies
Replies
Answer verified by a subject expert
slicealemonslicealemon
wrote...
Top Poster
Posts: 930
7 years ago Edited: A year ago, bio_man
Sign in or Sign up in seconds to unlock everything for free
More solutions for this book are available here
1

Related Topics

Chery Author
wrote...
7 years ago
You're right again!

Appreciate it
wrote...
3 years ago
m
wrote...
3 years ago
thank you
wrote...
A year ago
Quote
A guitar-like stringed instrument has a string that is 16 cm long. It sounds the musical note A when played without fingering. How far from the end of the string should you place your finger to play the note C

The frequency of the guitar = nv/2L

Here L is the length that is vibrating string

Take n=1 ,for fundamental case

In first case Full length vibrates
Therefore L=20 cm = 0.2 m
Therefore frequency 440=v/2*0.2
Therefore v=176 m/sec

In second case let the length of the vibrating string=l

523=176/2l
therefore l =0.168 m

Therefore the finger should be placed at a distance 16.8 cm from one end of the string
L u c k y  D u c k y
New Topic      
Explore
Post your homework questions and get free online help from our incredible volunteers
  595 People Browsing
 141 Signed Up Today
Related Images
  
 180
  
 918
  
 573
Your Opinion
What's your favorite coffee beverage?
Votes: 274

Previous poll results: How often do you eat-out per week?