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Chery Chery
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Posts: 3594
5 years ago
What is the wavelength of a 6.32-eV photon? (c = 3.00 × 108 m/s, h = 6.626 × 10-34 J ∙ s, 1 eV = 1.60 × 10-19 J)
A) 197 nm
B) 167 nm
C) 216 nm
D) 234 nm
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College Physics


Edition: 1st
Authors:
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noreyaganoreyaga
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5 years ago
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More questions for this book are available here
A

given E = 6.32 eV

c = 3.00 X 108 m / s,

h = 6.626 X 10-34 J • s

1 eV = 1.60 X 10-19 J

E = 6.32 X 1.6 X 10-19 J

E = 10.112 X 10-19

we have E = h c / \lambda

\lambda = h c / E

\lambda = 6.626 X 10-34 X 3.00 X 108 / 10.112 X 10-19

\lambda = 1.9878 X 10-25 / 10.112 X 10-19

\lambda = 1.9657 X 10-7

\lambda = 197 nm
1

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