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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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Sizacle Sizacle
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7 years ago
1.How many molecules of sodium carbonate are there in the above formula?
2.2 . What is the total of atoms of each of the elements in above the formula of sodium carbonate?
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bolbolbolbol
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Sizacle Author
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#2
7 years ago
3Na2CO3
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#3
Staff Member
7 years ago
a) Molecular weight calculation:
    23*2 + 12.0107 + 16*3 = 105.99 grams

For 1 mole of

105.99 grams Na2CO3 (1 mole Na2CO3/105.99 grams)(6.022 X 10^23/1 mole Na2CO3 molecules) =6.02*1023 molecules of  sodium carbonate

105.99 grams Na2CO3 (3 mole Na2CO3/105.99 grams)(6.022 X 10^23/3 mole Na2CO3 molecules) =6.02*1023 molecules of  sodium carbonate


b) Element     Symbol     Atomic Mass        # of Atoms          
Sodium      Na              22.9898           2                    
Carbon      C              12.0107           1                    
Oxygen      O              15.9994            3                      
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#4
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7 years ago
a) Molecular weight calculation:
    22.99*6 + 12.01*3 + 16*9 = 317.97 grams


317.97 grams Na2CO3 (3 mole Na2CO3/317.97 grams)(6.022 X 10^23/3 mole Na2CO3 molecules) =6.02*1023 molecules of  sodium carbonate

b) Element     Symbol     Atomic Mass        # of Atoms           
Sodium      Na              22.9898           6                     
Carbon      C              12.0107           3                   
Oxygen      O              15.9994            9


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