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Home Q & A Board Science-Related Homework Help High School Level Science
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boojis boojis
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11 years ago
If a women with  the genotype IAIB, Rh+ and a man with type O Rh- have a child, what is probability that child will have blood type A Rh-?
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Answer rejected by topic starter
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#1
11 years ago
A mother who is blood type AB could pass either an A or a B allele to her son or daughter.

A father who is blood type O can only pass an O allele to his son or daughter.

This couple could have children of either blood type A (O from father and A from mother) or blood type B (O from father and B from mother).

The child, therefore, will have equal chances of being either A or B blood type.
boojis Author
wrote...
#2
11 years ago
thats not answer to that question. Its a number.
wrote...
#3
Educator
11 years ago
Wouldn't it then be 50%, or 1:2 ?
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#4
10 years ago
The question is asking two things.

1. What's the probability of the child having a RH-
2. What's the probability of the child having A blood type

The Answer is 1/4 = 0.25

This is a question that a punnet square is optimal.

1. RH- = dd
   RH+ = Dd or DD (because they do not specify if it is homozygous Dominant you take the Dd)
 
  D      d
d Dd    dd    = 1/2 RH- 1/2 RH+
d Dd    dd

2.  ii = O
IAIB = AB

   IA     IB
ii IAii   IBii     = 1/2 A    1/2 B
ii IAii   IBii

1/2 (RH-) x 1/2 (A) = .25
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