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Northa Northa
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4 years ago
A proton is accelerated from rest through 500. V. It enters a magnetic field of 0.300 T oriented perpendicular to its direction of motion. Determine:
(a)   the radius of the path it follows.
(b)   the frequency with which it moves around this path.
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Physics


Edition: 4th
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Physics, 4th edition by Walker
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mtown88mtown88
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4 years ago
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More questions for this book are available here
(a)   0.011 m
(b)   4.57 MHz

0.5mv^2=qV

v=3.09*10^5m/s

r=mv/qB=0.01078m=1.078cm

f=v/2pi*r=4.56*10^6Hz
California State University Alumni

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