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wrote...
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6 years ago
PLEASE HELP US.
Calculate the concentration of HCL in water if 48.47 ml of the HCL solution is required to titrate a solution of 0.5015 grams of NaOH in water.
PLEASE.
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wrote...
Posts: 40
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6 years ago
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write a balanced equation

HCl(aq) + NaOH(aq) -----------> NaCl(aq) + H2O(l)

the balanced equation shows that 1 mole HCl neutralises 1 mole NaOH

moles NaOH = mass / molar mass
= 0.5015 g / 40.00 g/mol
= 0.0125375 moles NaOH

Since they react in a 1:1 ration then moles HCl needed = moles NaOH used
= 0.0125375 moles

So there were 0.0125375 moles HCl in the 48.47 ml

Molarity = moles / L
= 0.0125375 mol / 0.04847 L
= 0.2587 M (4 sig figs)
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