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tony1653 tony1653
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11 years ago
and how many moles are in 129.7 g of Fe3(PO4)2?
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wrote...
11 years ago
H2SO4 is 98.02 g/mol  It has 4 O's, so that would be 64 g/mol

So 64 / 98 = 65.3 %

moles = mass / Molar Mass
wrote...
11 years ago
Sulfuric acid: H2SO4

Molar mass sulfuric acid:
2 H x 1.008 = 2.016
1 S x 32.07 = 32.07
4 O x 16.00 = 64.00

Add them up we get, 98.086 g H2SO4.

Since molar mass of oxygen is 64 (4 O x 16), we do

64/98.086 x 100 = 65.2% oxygen

2. Grams -> mol

Given gram x 1 mol/molar mass

Molar mass Fe3(PO4)2:
3 Fe x 55.85 = 167.55
2 P x 30.97 = 61.94
8 O x 16.00 = 128.00

Add them up we get, 357.49 g Fe3(PO4)2

129.7 g Fe3(PO4)2 x 1 mol Fe3(PO4)2/357.49 g Fe3(PO4)2 = 0.3628 mol Fe3(PO4)2
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