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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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smmunday smmunday
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11 years ago
What is the molarity of Sodium Hydroxide solution if 37.34 mL of it are required to neutralize 1.922 g of citric acid?

Can you please explain how you get this answer.

Thank you.
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wrote...
#1
11 years ago
Citric acid moles = mass / molar mass = 1.922 / 192.2 = 0.01 moles.
Citric acid is triprotic there being 3 reacting H+ for each 0H-.
Sodium hydroxide moles = 0.01 x 3 = 0.03 moles.
0.03 moles / 0.03734 L

= 0.8034 M NaOH / ans.
.
Answer accepted by topic starter
michele12michele12
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#2
Posts: 20
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11 years ago
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