× Didn't find what you were looking for? Ask a question
Top Posters
Since Sunday
g
3
3
2
J
2
p
2
m
2
h
2
s
2
r
2
d
2
l
2
a
2
New Topic  
Datiyota Datiyota
wrote...
Posts: 22
Rep: 0 0
11 years ago
A toroid has u r = 600 and is wound with 550 turns of copper wire carrying a current of 2 A. It has a cross-sectional area of 4x10^-3m^2 and a mean radius of 100mm.
Find the magnetic field strength, magnetic flux and flux density in the core.

Also and explanation and working would be great since reading over the topic I wasn't sure of how to apply what the text book said since there were no worked examples.

Thanks.
Read 403 times
1 Reply

Related Topics

Replies
wrote...
11 years ago
to fine the flux of field...u hve to use this formula
B=munot N I/2 pie r
the value of mu not is constant..tht is.4(3.142) *10^-7 web/amp m
just put al those values in this formula..
B=4(3.142)x10^-7x550x2/(2x3.142x0.1)  convert 10mm into m which is radius by divinding with 1000.
B=2.2x10^-3 weber/m^2 or tesla
now u get magnetic field....for finding the magnetic flux density
this is a formula
magnetic flux=magnetic field * Area
magnetic flux=2.2x10^-3 * 4x10^-3
magnetic flux=8.8x10^-6 webers
now flux density
flux density=magnetic flux/area
flux density=8.8x10^-6/4x10^-3
flux density=2.2x10^-3 web/m^2
how u will get tht.
New Topic      
Explore
Post your homework questions and get free online help from our incredible volunteers
  1118 People Browsing
 131 Signed Up Today
Related Images
  
 84
  
 6929
  
 454
Your Opinion
What percentage of nature vs. nurture dictates human intelligence?
Votes: 431