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Vika123 Vika123
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6 years ago
At 500 ∘C, cyclopropane (C3H6) rearranges to propene (CH3−CH=CH2). The reaction is first order, and the rate constant is 6.7×10−4s−1. If the initial concentration of C3H6 is 4.50×10−2 M .

a) What is the half-life (in minutes) of this reaction?
b) How many minutes will it take for the concentration of cyclopropane to drop to 6.25% of its initial value?
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Valued Member
Educator
6 years ago
Hi! Good question. Here's what I know:

K1 = 0.693/t1/2

t1/2 = 0.693/6.7*10^-4

t1/2 = 1034.32 sec.

b)

K1 = 2.303/t log(initial/final)

6.7 *10^-4 = 2.303/t log(100/12.5)

time = 3104.203 sec

time = 51.736 min.
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