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princess001 princess001
wrote...
Posts: 324
Rep: 3 0
11 years ago
1. In a randomly mating population of mice, 25.0 out of every 100.0 mice born have white fur, a recessive trait.
     (a) Calculate the frequency of each allele in the population.
     (b) Calculate the genotype frequencies for the population.

2. Picture attachment asks for
If the individuals in this pedigree represented a distinct population, how many of the 21 people could be expected to be heterozygous for PKU?  ____________________ people.
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Answer accepted by topic starter
bio_manbio_man
wrote...
Educator
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Posts: 33241
11 years ago
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princess001 Author
wrote...
11 years ago
Thanks bio man
wrote...
Educator
11 years ago
2. Picture attachment asks for
If the individuals in this pedigree represented a distinct population, how many of the 21 people could be expected to be heterozygous for PKU?  ___________________ _ people.

I'd guess 7, but that's just by looking at the diagram.
wrote...
10 years ago
Does anyone know, or has anyone figured out the answer to the pedigree question? I have only one question left in my assignment, and that is the one I am stuck on! Help would be greatly appreciated, thank you (:
EA
wrote...
10 years ago
for the pedigree question, the book says p=0.5635642195. i got 10 as the answer. is that correct?
Post Merge: 10 years ago

2. Picture attachment asks for
If the individuals in this pedigree represented a distinct population, how many of the 21 people could be expected to be heterozygous for PKU?  ___________________ _ people.

I'd guess 7, but that's just by looking at the diagram.

heyy bio man could u look at my last post, thnx
wrote...
Educator
10 years ago
Hi there, are you referring to the PKA question?
wrote...
On Hiatus
10 years ago
thanks guys
Machiavelli
wrote...
9 years ago
Hi there, are you referring to the PKA question?

Do you know the answer to this question...I am stuck on this one...
wrote...
4 years ago
I got 10 people for the pedigree question, as well.


q(2) =      4/21 = 0.1904761
then you square root 0.1904761 = 0.43643
q = 0.436443

1 - q = p
1 - 0.43643 = 0.563564
p = 0.563564

2pq = (2)(0.563564)(0.436443)
= 0.49

then multiple it by the total amount of individuals
(0.49)(21) = 10.29

so I think it is 10 people
wrote...
3 years ago
.
wrote...
3 years ago
thank you
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