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juelz juelz
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11 years ago
The legs of the triangle are 3cm and 4cm and two sides of the rectangle lie along the legs.

This is an optimization problem where I need to maximize the area of the rectangle.  My problem here is finding a way to get the area of the rectangle in terms of one variable.

Using common sense, I do know that the area of the triangle is 6 cm^2 and the area of the rectangle must be smaller than this.
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smartgirlsmartgirl
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11 years ago
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wrote...
11 years ago
Okay, imagine it set up on a coordinate system.
Then we know that y/x=4/3.
And the area of rectangle is (3-x)y = (3-x)(4x/3)
=4x-4x^2/3
Now diiferinate and set to 0, giving you
4-8x/3=0, or 4=8x/3.
So, x=12/8=3/2.
SO, the area is (3-3/2)((4/3)(3/2)) = (3/2)(2)
=3. SO, maximum area is 3.
wrote...
11 years ago
Use similar triangles.  x/(3-y)=4/3

y=3-(3x/4)

Area of rectangle is xy

A=x(3-(3x/4))

A'=3-3x/2

3-3x/2=0

x=2 and y=3/2
wrote...
11 years ago
2*1
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