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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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fieldhockey32 fieldhockey32
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11 years ago
Questions asks: The following electrochemical cell has a potential of .55v at 25C.
Pt | H2 (g, 1.00atm) | H+(aq, 1.00 M) || Ag+(aq) | Ag

The standard reduction potential, E of Ag+ = +.80v. What is the Ag+ concentration?

If anyone known the precise answers i would greatly apreciate, and also the steps would be great to know too. Thanks.
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#1
11 years ago
electrode to the left is SHE and his potential is = 0
E cell = E Ag - E SHE = E Ag = 0.55 V
E Ag = 0.80+0.059*log [Ag+] = 0.55 V
log[Ag+] = (0.55-0.80) / 0.059 = -4.237
[Ag+] = 10^(-4.237) = 5.79*10^-5 M
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