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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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riptose riptose
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11 years ago
The pH of 0.1 M HClO2 (chlorous acid) aqueous solution was measured to be 1.2. What is the value of pKa for chlorous acid?
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#1
11 years ago
Initial condition
[HClO2] = 0.10
[H+] = 0
[ClO2-] = 0

after x moles of HClO2 dissociate, the change in concentrations is

?[HClO2] = -x
?[H+] = +x
?[ClO2-] = +x

equilibrium  concentrations

HClO2] = 0.10 - x
[H+] = x
[ClO2-] = x

Ka = [H+]*[ClO2-]/[HClO2]  from the pH you get [H+] = 0.0631 M; then x = 0.0631 and 0.10 - x = 0.9369

Ka = 0.0631²/0.9369 = 0.004250

pKa = -log(Ka) = 2.37
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