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nzp123 nzp123
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Posts: 122
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10 years ago
A solution of hydochloric acid has a density of 1.15 grams per milliliter and is 30.0% by weight HCl.
(a) what is the molarity of this solution of HCl?
(b) What volume of this solution ahouls be taken in order to prepare 5.0 liters of 20.0 molar hydrochloric acid by dilution with water?
HEElpPP!
(b) What volume of this solution ahouls be taken in order to prepare 5.0 liters of 0.20 molar hydrochloric acid by dilution with water?
Sorry for the confusion!
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2 Replies
Replies
wrote...
10 years ago
a) 30.0% by weight.

Assume 100 g, so 30.0 g of that is HCl.

30.0 g / 36.5 g/mol = 0.822 moles

Solution weighs 100 g, which given the density is 87.0 ml, or 0.087 L

molarity = moles solute / L solution = 0.822 moles / 0.087 L = 9.45 M

b) It's impossible to make a 20.0 M HCl solution, as the highest weight percent solution that can be made of HCl is about 37% (which is roughly 12 M).
Answer accepted by topic starter
tom_andrewstom_andrews
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10 years ago
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