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Home Q & A Board Laboratory Help Introductory Courses
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smiley13 smiley13
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10 years ago
Well one question in this chemistry lab asks us to determine the molar concentration (molarity).

We have 10mL of acetic acid (vinegar) in a 100mL solution where the rest is water.

I'm pretty sure i'm getting the wrong answer so could anyone show me how to get molarity (mol/L)?
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#1
10 years ago
you need to know the density of vinegar in order to figure out how many grams there are in order to figure out how many moles of acetic acid you have.  

Molarity= moles of solute/Total Liters of solution
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#2
10 years ago
the density is 1.05 g/mL
so you need to do 10mL x 1.05 g/mL = 10.5 g
then figure out how many moles are in 10.5g of acetic acid by dividing 10.5 by the molecular maaa of acetic acid. (which will equal x)
then do x/100 mL which will give you the molarity (mol/mL) and then convert mL into L by multiplying it by 1000.
hope this isnt too confusing but i dont have my calculator on me
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