× Didn't find what you were looking for? Ask a question
Top Posters
Since Sunday
g
3
3
2
J
2
p
2
m
2
h
2
s
2
r
2
d
2
l
2
a
2
Home Q & A Board Biology-Related Homework Help Genetics and Developmental Biology
New Topic  
jtoya18 jtoya18
wrote...
Posts: 3
Rep: 1 0
10 years ago
In a dihybrid cross that follows the pattern of inheritance of two traits (yellow/green (Yy), and round/wrinkled (Rr) peas the F1 generation with genotype RrYy were self-cross. What is the probability of getting a pea with the genotype RRYY?

I don't care if answer is percentage or fraction...
Read 323 times
3 Replies

Related Topics

Replies
wrote...
#1
10 years ago
25%
wrote...
#2
10 years ago
25%

1/4

one in four

I think XD
wrote...
#3
10 years ago
1/16.

You could either do the 4x4 Punnett square, RrYy x RrYy, or you could do the 2 genes separately:  The chance of getting RR from Rr x Rr is 1/4:

____R____r___
R__RR___Rr__
r___Rr___rr___

The same is true of getting YY from Yy x Yy.

And 1/4 x 1/4 is 1/16.
New Topic      
Quick Reply
Explore
Post your homework questions and get free online help from our incredible volunteers
  1083 People Browsing
 126 Signed Up Today
Start New Topic Take the Tour CoursesNew Study Tools Topics Trending Browse by Textbook
Live Chat
Related Images
  
 20
  
 262
  
 320
Your Opinion
Which country would you like to visit for its food?
Votes: 204
Previous poll results: Which 'study break' activity do you find most distracting?