Finding Mayan Dates

Given the Mayan date (8,10,193) find the date that is 0,2,3,5,10 days later.   

The Mayan calendar system was complex. They used two calendars at the same time. The first was a 260 day almanac system - which was comprised of two cycles, one of length 13 and the other 20 long. Any day in the almanac is written as (t,v) where t is a number from 1 to thirteen, and v is one of twenty day names. The second calendar has 18 months of twenty days, plus an extra five days. This can simply be designated as a number from one to 365.   

I don't understand how to find the date that is a certain number of days later. Can anyone help me?