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Home Q & A Board Biology-Related Homework Help General Biology
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hongan hongan
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10 years ago
Take the solution to problem 1d, add 10 mL of denionized water, and cool the solution to 0 degreesCelsius.

1. How much KNO3 remains in the solution?

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10 years ago
Hi--

Question:

Quote
It takes 11.53 grams of water to dissolve a mixture of 25 grams of KNO3 and 2 g of CuSO4 at 100 degrees C. If 10 milliliters of deoionized water is added and the solution is cooled to 0 degrees C.

a. How much KNO3 remains in the solution?

b. How much KNO3 crystallizes out?

c. How much CuSO4 crystallizes out?

d. What percentage of KNO3 is recovered from the original 25 grams

Answer:

Quote
Chemistry is metric, and in this system volume is equivalent to weight when dealing with water. Therefore, 11.53 grams of water is also the volume in milliliters.

The final volume is 11.53 + 10 = 21.53 mls. If 10g of KNO3 dissolve in 100 mls of water at 0 C, then 10g/100mls = 0.1 gm/ml. 21.53 mls will dissolve (21.53 mls)*(0.1 gm/ml) = 2.153 gm KNO3. 25 gm - 2.153 gm = 22.847 gm of KNO3 will crystalize out of the solution.

The calculations for the CuSO4 work exactly the same.
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