× Didn't find what you were looking for? Ask a question
Top Posters
Since Sunday
g
3
3
2
J
2
p
2
m
2
h
2
s
2
r
2
d
2
l
2
a
2
New Topic  
Spice Spice
wrote...
Posts: 21
Rep: 0 0
10 years ago
1- A solution is 6.53% K2SO4. An experiment require 5.54g K2SO4. How many grams of the solution do you need for this experiment?

2- An aqueous solution made from 0.758g of barium chloride, BaCl2. If the volume of the solution is 52.80mL, What is the molarity of barium chloride in the solution?

3- How many milliliters of 0.130 M  Na3PO4 are required to give 0.0165 mol of sodium phosphate, Na3PO4?


Thank you!!!!
Read 599 times
1 Reply

Related Topics

Replies
wrote...
Donated
Valued Member
10 years ago
1.
\(\frac{100 g solution}{6.53 g {{K}_{2}}{{SO}_{4}}}*5.54 g {{K}_{2}}{{SO}_{4}}\) = 84.8 g solution

2.
\(\frac{0.758 g {{BaCl}_{2}}}{52.80 mL {{BaCl}_{2}}}*\frac{1 mol {{BaCl}_{2}}}{208.2324 g {{BaCl}_{2}}}*\frac{1000 mL}{1 L}\) = 0.0689 M BaCl2 solution

3.
\(\frac{1 L {{Na}_{3}}{{PO}_{4}}}{0.130 mol {{Na}_{3}}{{PO}_{4}}}*0.0165 mol {{Na}_{3}}{{PO}_{4}}*\frac{1000 mL}{1 L}\) = 127 mL Na3PO4 solution
Pretty fly for a SciGuy
New Topic      
Explore
Post your homework questions and get free online help from our incredible volunteers
  865 People Browsing
 125 Signed Up Today
Related Images
  
 1019
  
 1861
  
 4766
Your Opinion
Which industry do you think artificial intelligence (AI) will impact the most?
Votes: 352

Previous poll results: What's your favorite math subject?