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Title: PhysioEx 9 EX 5 Activity 4 Question Post by: Da_Capo on Oct 9, 2011 Can anybody help me with this problem? Use your date to calculate the increase in flow rate in ml/min/mm Hg. I'm not even sure how to set up the problem. :thi: My data is as follows: mm/hg ml/mi 20 35.0 50 70.1 75 105.1 100 140.2 125 175.2 150 210.3 175 245.3 200 280.4 Any help is much appreciated. I have almost all of it done up until there if anyone else needs help with previous questions. Title: Re: PhysioEx 9 EX 5 Activity 4 Question Post by: duddy on Oct 9, 2011 Don't you use: Rate of Change = (y2 - y1) / (x2 - x1) ?
Remember, if you were to plot this, the graph should be linear because the relationship between pressure and blood flow is linear. Title: Re: PhysioEx 9 EX 5 Activity 4 Question Post by: Da_Capo on Oct 9, 2011 :-\
So let me see if I'm on the right track...... the rate of change will stay constant since it is linear so I will only have to use the difference between two different pressure settings: the x's are the difference in ml/mm readings 70.1-35=35.1 and the y's are the difference in mm/hg reading 50-20=30 Making the answer I think :thi: 30/35.1 ml/min/hg Did I do this correctly? It has been a very long time since I've needed any math. Title: Re: PhysioEx 9 EX 5 Activity 4 Question Post by: Da_Capo on Oct 9, 2011 Content hidden
Title: Re: PhysioEx 9 EX 5 Activity 4 Question Post by: bio_man on Oct 10, 2011 30/35.1 ml/min/hg Yes, thanks Duddy, and you've done the correct calculation. Title: Re: PhysioEx 9 EX 5 Activity 4 Question Post by: Da_Capo on Oct 10, 2011 :thi:
I'm not quite sure I get it yet.... ??? Should the answer be expressed as a fraction and why or why not? Thanks! Title: Re: PhysioEx 9 EX 5 Activity 4 Question Post by: cindybev on Mar 4, 2012 When I calcluate the slope of the line, I am getting 1.4. Did you get your grade back for this? Was your calculation correct, or was it 1.4?
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