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nevada nevada
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Posts: 116
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12 years ago
A piece of aluminum with a mass of 250. g is at an initial temperature of 5.0 °C. If 24.1 kJ is supplied to warm the Al, what is its final temperature?

the specific heat capacity of Al is 0.902J g^-1 ºC


what is did, is i set it up like this

deltaT = q/ c X m

delta T= 5.0
c=0.902
m=250g

giving me this

5.0 X 24.1/ 0.902 X 250 =0.534368071

idk if this is right

in the book there are different formula

such as

c= q / m X Delta T

Delta T = q / c X m OR q = c X m X delta T
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