Transcript
SOLUTIONS TO SELECTED PROBLEMS
Student: You should work the problem completely before referring to the solution.
CHAPTER 14
Solutions included for problems 1, 4, 7, 10, 13, 16, 19, 22, 25, 28, 31, 34, 37, 40, 43,
46, and 49
Inflated dollars are converted into constant value dollars by dividing by one
plus the inflation rate per period for however many periods are involved.
14.4 Then-current dollars = 10,000(1 + 0.07)10
= $19,672
14.7 CV0 for amt in yr 1 = 13,000/(1 + 0.06)1
= $12,264
CV0 for amt in yr 2 = 13,000/(1 + 0.06)2
= $11,570
CV0 for amt in yr 3 = 13,000/(1 + 0.06)3
= $10,915
14.10 (a) At a 56% increase, $1 would increase to $1.56. Let x = annual increase.
1.56 = (1 + x)5
1.560.2 = 1 + x
1.093 = 1 + x
x = 9.3% per year
(b) Amount greater than inflation rate: 9.3 – 2.5 = 6.8% per year
14.13 if = 0.04 + 0.27 + (0.04)(0.27)
= 32.08% per year
14.16 For this problem, if = 4% per month and i = 0.5% per month
0.04 = 0.005 + f + (0.005)(f)
1.005f = 0.035
f = 3.48% per month
14.19 Buying power = 1,000,000/(1 + 0.03)27
= $450,189
14.22 (a) PWA = -31,000 – 28,000(P/A,10%,5) + 5000(P/F,10%,5)
= -31,000 – 28,000(3.7908) + 5000(0.6209)
= $-134,038
PWB = -48,000 – 19,000(P/A,10%,5) + 7000(P/F,10%,5)
= -48,000 – 19,000(3.7908) + 7000(0.6209)
= $-115,679
Select Machine B
(b) if = 0.10 + 0.03 + (0.10)(0.03) = 13.3%
PWA = -31,000 – 28,000(P/A,13.3%,5) + 5000(P/F,13.3%,5)
= -31,000 – 28,000(3.4916) + 5000(0.5356)
= $-126,087
PWB = -48,000 – 19,000(P/A,13.3%,5) + 7000(P/F,13.3%,5)
= -48,000 – 19,000(3.4916) + 7000(0.5356)
= $-110,591
Select machine B
(a) New yield = 2.16 + 3.02
= 5.18% per year
(b) Interest received = 25,000(0.0518/12)
= $107.92
14.28 740,000 = 625,000(F/P,f,7)
(F/P,f,7) = 1.184
(1 + f)7 = 1.184
f = 2.44% per year
In constant-value dollars, cost will be $40,000.
14.34 Future amount is equal to a return of if on its investment
if = (0.10 + 0.04) + 0.03 + (0.1 + 0.04)(0.03) = 17.42%
Required future amt = 1,000,000(F/P,17.42%,4)
= 1,000,000(1.9009)
= $1,900,900
Company will get more; make the investment.
14.37 if = 0.15 + 0.06 + (0.15)(0.06) = 21.9%
AW = 183,000(A/P,21.9%,5)
= 183,000(0.34846)
= $63,768
14.40 Find amount needed at 2% inflation rate and then find A using market rate.
F = 15,000(1 + 0.02)3
= 15,000(1.06121)
= $15,918
A = 15,918(A/F,8%,3)
= 15,918(0.30803)
= $4903
14.43 (a) For CV dollars, use i = 12% per year
AWA = -150,000(A/P,12%,5) – 70,000 + 40,000(A/F,12%,5)
= -150,000(0.27741) – 70,000 + 40,000(0.15741)
= $-105,315
AWB = -1,025,000(0.12) – 5,000
= $-128,000
Select Machine A
(b) For then-current dollars, use if
if = 0.12 + 0.07 + (0.12)(0.07) = 19.84%
AWA = -150,000(A/P,19.84%,5) – 70,000 + 40,000(A/F,19.84%,5)
= -150,000(0.3332) – 70,000 + 40,000(0.1348)
= $-114,588
AWB = -1,025,000(0.1984) – 5,000
= $-208,360
Select Machine A
14.46 Answer is (d)
14.49 Answer is (a)
Chapter 14 3
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