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Description
Physics for Bioscience (II)
Transcript
Administration
Electrical Safety I
Electrical Safety II
Electrical Safety III
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Instructor
Franco Gaspari
PHY 1040U
(Physics for the biosciences)
Introduction to Electromagnetism and Optics
Lecture 13
March 02, 2007
Ideal versus real battery
An ideal source of emf maintains a constant potential difference between its terminals, independent of the current, I, through it or the resistance, R, across it. The formula for an ideal source of emf
V
Thus the equation for a source with internal resistance is
Example of loop rule, resistance rule and emf rule (single loop).
Resistors in series
The current is the same through each resistor since any charge that flows through R1 must flow through R2 (KCL).
Potential drop from a to b IR1
Potential drop from b to c IR2
In general, for resistors in series
X-mas lights
Resistors in parallel
At the junction at a the current splits in 2, i.e., I I1 I2 (KCL).
Since the potential drop is the same, we have
Household circuits are always in parallel.
Examples (series, parallel, Kirchhoff)
Example 28.4 page 866
The Ammeter and the Voltmeter
R for ammeters is very small.
R for voltmeters is very large.
I1
I2
R1
R2
Why
The current passes directly through the ammeter.
Since the resistance of the ammeter is in series, then
We place the voltmeter between the 2 terminals of a resistor to measure the potential drop.
However, with the voltmeter connected, in reality we measure
1. A battery has an emf of 15.0 V. The terminal voltage of the battery is 11.6 V when it is delivering 20.0 W of power to an external load resistor R. (a) What is the value of R (b) What is the internal resistance of the battery
An emf is the potential of the battery without considering the internal resistance.
The terminal voltage is the actual potential at the output of the battery terminals (that is, including the internal resistance)
From the definition of Power, we get
Where V is the terminal voltage, then
M
6. (a) Find the equivalent resistance between points a and b in the Figure. (b) A potential difference of 34.0 V is applied between points a and b. Calculate the current in each resistor.
We are now left with 3 resistors in series, then
The current across the 3 resistors in series is the same, that is
I 1
I 2
The current I splits into I1 and I2 when it meets the 2 resistors in parallel. The potential drop across the resistors in parallel is
Fig 28-32a, p.882
Fig 28-32b, p.882
Figure 28.32 (b) This shock can be avoided by connecting the drill case to ground through a third ground wire. In this situation, the drill case remains at ground potential and no current exists in the person.
t
Then, by rearranging the terms in the equation, solving for Rshoes
Figure 28.32 (b) This shock can be avoided by connecting the drill case to ground through a third ground wire. In this situation, the drill case remains at ground potential and no current exists in the person.
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