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oaghasey oaghasey
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11 years ago
Trigonometry test
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11 years ago
sina/A = sinb/B
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11 years ago
You need 2 angles and another length to do this.

Let's say you have a triangle with angle 34° opposite to a side of length 5 and an angle of 41° opposite to your unknown side.

Applying a/sin(A) = b/Sin(B)

Substitute values:

a/sin(41°) = 5/sin(34°)

a = 5sin(41°)/sin(34°) (At this point use your calculator to find the value, or use exact values if applicable).

If you're given two angles and a side opposite the unknown angle, then use the angles in a triangle sum to 180° to find the relevant angle.

For example: if you have angles 75° and 46° and you need to use the last angle to solve the equation, then use 180 - 75 - 46 = 59°
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