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cloveb cloveb
wrote...
Valued Member
Posts: 782
7 years ago
A body of mass 5.0 kg is suspended by a spring which stretches a distance delta y when the mass is attached. It is then displaced downward an additional 5.0 cm and released. Its position as a function of time is given by
 y = 0.05 cos (9.9 t + 0.1). What is the value of delta y ?

a. 0.1 cm
b. 0.1 m
c. 0.05 m
d. 0.5 m
e. none of the above
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Answer accepted by topic starter
5seal5seal
wrote...
Posts: 147
7 years ago
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