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firetruckboom firetruckboom
wrote...
Posts: 79
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11 years ago
ABC is a triangular paddock, with its measurements as shown: (diagram) A=Right angled, c=2km, a=3km.

What I need help on is part c) , I've done the rest as shown:
Find:

a) the perimeter of the paddock.
Pythagorean theorem, found side b (=2.24km) then added the sides up = 7.74 km
b) the area of the paddock in hectares
1/2*2*2.24= 2.24km^2
1km squared= 100 hectares
so 224 hectares
c)the shortest distance from A to the fence joining BC.  Hint: Use b)

How am I supposed to use the area to find the height of the new-formed right triangle?  I don't want to have to resort to using sin and cos rules as no mention of such use was needed in this chapter I'm studying.
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wrote...
11 years ago
To find the shortest distance from A to the fence joining BC, remember that the point A must project at BC, forming the right angle, so this means that you will need to consider forming the perpendicular lines on the diagram or use dot product or perform the appropriate linear graph, depending on your choice.  It's all up to you to decide which method to use.

Good luck!
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