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paigevictoria11 paigevictoria11
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Posts: 10
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10 years ago
An aluminum electric tea kettle has a mass of 500 g. It has a 500-W heating coil. How long will it take to heat up 1.0 kg of water from 18°C to 98°C in the tea kettle? The specific heat of aluminum is 900 J/(kg K).
A) 5 minutes B) 7 minutes C) 12 minutes D) 15 minutes
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wrote...
Staff Member
Educator
10 years ago
Please do a search before posting - forum rules.

https://biology-forums.com/index.php?topic=16767.0
Mastering in Nutritional Biology
Tralalalala Slight Smile
wrote...
Valued Member
On Hiatus
10 years ago
If you need the detailed answer:


We have Q=cmΔT (c is specific heat, m is mass, ΔΤ is temperature change, Q is heat)

We have to find the heat required to change the temperature of the aluminum and the water

For the aluminum:
500g=0,5kg:
Q aluminum =900*0,5*80=27000J

For the water: specific heat = 1cal/g*K= 4,18jj/g*K= 4180j/kg*K
So,
Q water=4180*1*80=334400J

TOTAL HEAT NEEDED: Q=334400 + 27000 = 361400J
TIME NEEDED TO PROVIDE THAT HEAT: T=Q/W=722,8sec=12,0467min (C)
wrote...
Staff Member
Educator
10 years ago
Upwards Arrow Genious
Mastering in Nutritional Biology
Tralalalala Slight Smile
wrote...
10 years ago
@ALEXX WOW! alexx thank you for all of your help, you have helped me wonders with these problems, now i see how you do it! ( thanks to your help!)
-to take the time out of your day to help me is very nice of you, there are not many people like you in the world.. THANK YOU again, for all of your help
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