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CTaustin CTaustin
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6 years ago
Of 81 adults selected randomly from one town, 63 have health insurance. Find a 90 confidence interval for the true proportion of all adults in the town who have health insurance.
 
  A) 0.670 < p < 0.885 B) 0.687 < p < 0.868 C) 0.702 < p < 0.854 D) 0.659 < p < 0.897
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wpingwping
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6 years ago
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CTaustin Author
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6 years ago
Helped a lot
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Yesterday
I appreciate what you did here, answered it right Smiling Face with Open Mouth
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2 hours ago
Thanks for your help!!
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