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Analyze the following code:public class Test { public static void main (String args[]) {int i = ...

melinoma86

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Analyze the following code:public class Test { public static void main (String args[]) {int i = ...

Analyze the following code:

public class Test {
public static void main (String args[]) {

int i = 0;

for (i = 0; i < 10; i++);

System.out.println(i + 4);

}
}

▸ The program compiles despite the semicolon (;) on the for loop line, and displays 4.

▸ The for loop in this program is same as for (i = 0; i < 10; i++) { }; System.out.println(i + 4);

▸ The program has a compile error because of the semicolon (;) on the for loop line.

▸ The program compiles despite the semicolon (;) on the for loop line, and displays 14.

Textbook

Introduction to Java Programming, Comprehensive Version

Edition: 10^th

Author: Liang

Read 66 times

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emnevius

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More solutions for this book are available here

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