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lara lara
wrote...
14 years ago
If 100 individuals of an F2 population derived from parent A and parent B were analysed for 80 markers across the genome, the numbers of markers that will display heterozygosity in 50 individuals is:
A) 10
B) 20
C) 40
D) 60
E) 80
Pleaasse help, I just have no idea what the question is even asking! Could you please explain why you would pick your answer and the steps you took to work it out as well?
Thank you so so much.
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wrote...
Educator
14 years ago
I have no idea either; it would probably help if you mentioned your textbook - we have solution manuals Undecided.
wrote...
14 years ago
(c) 40

heterozygosity = [(50) * (80)] / 100 = 40
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