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lensley lensley
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11 years ago
A juggler throws a ball straight up into the air and it takes 4.60 seconds to reach its peak. How many seconds will it take after that to fall back into his hand? Assume he throws and catches the ball at the same height.
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wrote...
11 years ago
The trajectory of the balls must be symmetric, meaning it takes the ball the same amount of time to travel back down to the original height it was juggled from as it does to reach its peak. So it must take another 4.60 s.
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