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tonesack tonesack
wrote...
11 years ago
How would I solve this exponential equation and similar problems?
5^2x=20

And how would I solve thi logarithmic equation?
log4=-1

Please help!
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Answer accepted by topic starter
nutzshells Authornutzshells
wrote...
11 years ago
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wrote...
11 years ago
5^(2x) = 20

2x log 5 = log (4·5)
x = (log 4 + log 5)/(2log 5)

x= (2log 2)/(2 log 5) + (log 5)/(2log 5) =
= (log 2)/(log 5) + 1/2
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