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bewley bewley
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Posts: 252
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7 years ago
A 72.0-kg person pushes on a small doorknob with a force of 5.00 N perpendicular to the surface of the door.  The doorknob is located 0.800 m from axis of the frictionless hinges of the door.  The door begins to rotate with an angular acceleration of 2.00 rad/s2.  What is the moment of inertia of the door about the hinges?
A) 4.28 kg • m2
B) 7.52 kg • m2
C) 1.88 kg • m2
D) 0.684 kg • m2
E) 2.74 kg • m2
Textbook 
Principles & Practice of Physics

Principles & Practice of Physics


Edition: 1st
Author:
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Answer verified by a subject expert
alblovealblove
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Posts: 115
7 years ago Edited: 2 years ago, bio_man
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bewley Author
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7 years ago
Thank you
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