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4bio 4bio
wrote...
Posts: 47
Rep: 3 0
6 years ago
Suppose that sample of beef broth initially contains 16 bacterial cells. After 4.0 h, there are 1.6 x 10^6 bacterial cells in the sample. Calculate the growth rate of the bacterial population for the given time interval.
1 mark

Record the answer in scientific notation: x X 10n, rounded to one decimal place.

 ______X 10^_ bacteria / hour
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wrote...
6 years ago
PR= V(present)- V(past) divided by V(past)x100


PR= (1.6x106)- 16
-------------
16
PR= 153.6
-----
16
PR= 9.5 x 100
wrote...
6 years ago
What is the answer to this question in the form of x X 10n?
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