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ripsmithy ripsmithy
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11 years ago
What is the energy in J of 1 photon whose frequency is 6.24 x 1014 hertz (cycles per second)? Use scientific notation.
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wrote...
11 years ago
Energy E = h.f
h = Planck's constant = 6.63 * 10^-34 Js
so E = 6.63 * 10^-34 Js * 6.24 * 10^14 Hz = 4.14 * 10^-19 J
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