What is the energy of a microwave photon with a wavelength of 5.25 cm?

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Planck's formula states the energy (E) is directly proportional to the frequency (f)
by: E = hf, where h is Planck's constant, equal to 6.625 * 10**-34 Joule-seconds.
The wavelength (w) is inversely proportional to f by: w = c/f where c is the speed of
light, equal to 3.0 * 10**8 meters per second. If we combine both these formulas,
we obtain: E = hc/w.  Since h and c are constants their product (hc) is constant
equal to 1.9875 * 10**-25 joule-meters. There are 6.28 * 10**18 electron-volts in
one joule, so we can multiply that constant by 6.28 * 10**18 and now the formula
becomes: E = 12.48 * 10**-7 eV-meter / w. Now we can find the energy from w:
A . If w = 5.25 cm. or 5.25 * 10**-2 meter, E = (12.48 * 10**-7) / (5.25 * 10**-2)
Then E = 2.377 * 10**-5 joule if w = 5.25 cm.
We can use the same formula for B and C:
B. E = (12.48 * 10**-7 eV-m) / (5.25 * 10**-7m) = 2.377 eV.
C. E = 237.7 eV